3.2353 \(\int \frac{(1-2 x)^{3/2} (3+5 x)^{5/2}}{2+3 x} \, dx\)

Optimal. Leaf size=150 \[ \frac{1}{12} (1-2 x)^{3/2} (5 x+3)^{5/2}+\frac{23}{216} \sqrt{1-2 x} (5 x+3)^{5/2}-\frac{53}{192} \sqrt{1-2 x} (5 x+3)^{3/2}-\frac{15863 \sqrt{1-2 x} \sqrt{5 x+3}}{20736}+\frac{648919 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{62208 \sqrt{10}}+\frac{14}{243} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right ) \]

[Out]

(-15863*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/20736 - (53*Sqrt[1 - 2*x]*(3 + 5*x)^(3/2))/192 + (23*Sqrt[1 - 2*x]*(3 + 5
*x)^(5/2))/216 + ((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/12 + (648919*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(62208*Sqrt[
10]) + (14*Sqrt[7]*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/243

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Rubi [A]  time = 0.064069, antiderivative size = 150, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269, Rules used = {101, 154, 157, 54, 216, 93, 204} \[ \frac{1}{12} (1-2 x)^{3/2} (5 x+3)^{5/2}+\frac{23}{216} \sqrt{1-2 x} (5 x+3)^{5/2}-\frac{53}{192} \sqrt{1-2 x} (5 x+3)^{3/2}-\frac{15863 \sqrt{1-2 x} \sqrt{5 x+3}}{20736}+\frac{648919 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{62208 \sqrt{10}}+\frac{14}{243} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/(2 + 3*x),x]

[Out]

(-15863*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/20736 - (53*Sqrt[1 - 2*x]*(3 + 5*x)^(3/2))/192 + (23*Sqrt[1 - 2*x]*(3 + 5
*x)^(5/2))/216 + ((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/12 + (648919*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(62208*Sqrt[
10]) + (14*Sqrt[7]*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/243

Rule 101

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a +
b*x)^m*(c + d*x)^n*(e + f*x)^(p + 1))/(f*(m + n + p + 1)), x] - Dist[1/(f*(m + n + p + 1)), Int[(a + b*x)^(m -
1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[c*m*(b*e - a*f) + a*n*(d*e - c*f) + (d*m*(b*e - a*f) + b*n*(d*e - c*f))
*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && GtQ[m, 0] && GtQ[n, 0] && NeQ[m + n + p + 1, 0] && (Integ
ersQ[2*m, 2*n, 2*p] || (IntegersQ[m, n + p] || IntegersQ[p, m + n]))

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 157

Int[(((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/((a_.) + (b_.)*(x_)), x_Symbol]
:> Dist[h/b, Int[(c + d*x)^n*(e + f*x)^p, x], x] + Dist[(b*g - a*h)/b, Int[((c + d*x)^n*(e + f*x)^p)/(a + b*x
), x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 93

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{(1-2 x)^{3/2} (3+5 x)^{5/2}}{2+3 x} \, dx &=\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}-\frac{1}{12} \int \frac{\left (-29-\frac{115 x}{2}\right ) \sqrt{1-2 x} (3+5 x)^{3/2}}{2+3 x} \, dx\\ &=\frac{23}{216} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}-\frac{1}{540} \int \frac{\left (-\frac{425}{2}-\frac{7155 x}{4}\right ) (3+5 x)^{3/2}}{\sqrt{1-2 x} (2+3 x)} \, dx\\ &=-\frac{53}{192} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{23}{216} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}+\frac{\int \frac{\sqrt{3+5 x} \left (\frac{94995}{4}+\frac{237945 x}{8}\right )}{\sqrt{1-2 x} (2+3 x)} \, dx}{6480}\\ &=-\frac{15863 \sqrt{1-2 x} \sqrt{3+5 x}}{20736}-\frac{53}{192} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{23}{216} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}-\frac{\int \frac{-\frac{3181875}{8}-\frac{9733785 x}{16}}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx}{38880}\\ &=-\frac{15863 \sqrt{1-2 x} \sqrt{3+5 x}}{20736}-\frac{53}{192} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{23}{216} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}-\frac{49}{243} \int \frac{1}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx+\frac{648919 \int \frac{1}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx}{124416}\\ &=-\frac{15863 \sqrt{1-2 x} \sqrt{3+5 x}}{20736}-\frac{53}{192} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{23}{216} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}-\frac{98}{243} \operatorname{Subst}\left (\int \frac{1}{-7-x^2} \, dx,x,\frac{\sqrt{1-2 x}}{\sqrt{3+5 x}}\right )+\frac{648919 \operatorname{Subst}\left (\int \frac{1}{\sqrt{11-2 x^2}} \, dx,x,\sqrt{3+5 x}\right )}{62208 \sqrt{5}}\\ &=-\frac{15863 \sqrt{1-2 x} \sqrt{3+5 x}}{20736}-\frac{53}{192} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{23}{216} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{12} (1-2 x)^{3/2} (3+5 x)^{5/2}+\frac{648919 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{3+5 x}\right )}{62208 \sqrt{10}}+\frac{14}{243} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{3+5 x}}\right )\\ \end{align*}

Mathematica [A]  time = 0.0851233, size = 110, normalized size = 0.73 \[ \frac{30 \sqrt{5 x+3} \left (172800 x^4-75840 x^3-121992 x^2+53578 x+2389\right )-648919 \sqrt{10-20 x} \sin ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )+35840 \sqrt{7-14 x} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{622080 \sqrt{1-2 x}} \]

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/(2 + 3*x),x]

[Out]

(30*Sqrt[3 + 5*x]*(2389 + 53578*x - 121992*x^2 - 75840*x^3 + 172800*x^4) - 648919*Sqrt[10 - 20*x]*ArcSin[Sqrt[
5/11]*Sqrt[1 - 2*x]] + 35840*Sqrt[7 - 14*x]*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/(622080*Sqrt[1 - 2*
x])

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Maple [A]  time = 0.012, size = 132, normalized size = 0.9 \begin{align*}{\frac{1}{1244160}\sqrt{1-2\,x}\sqrt{3+5\,x} \left ( -5184000\,{x}^{3}\sqrt{-10\,{x}^{2}-x+3}-316800\,{x}^{2}\sqrt{-10\,{x}^{2}-x+3}+648919\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ) -35840\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) +3501360\,x\sqrt{-10\,{x}^{2}-x+3}+143340\,\sqrt{-10\,{x}^{2}-x+3} \right ){\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x),x)

[Out]

1/1244160*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(-5184000*x^3*(-10*x^2-x+3)^(1/2)-316800*x^2*(-10*x^2-x+3)^(1/2)+648919*
10^(1/2)*arcsin(20/11*x+1/11)-35840*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))+3501360*x*(-10*
x^2-x+3)^(1/2)+143340*(-10*x^2-x+3)^(1/2))/(-10*x^2-x+3)^(1/2)

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Maxima [A]  time = 2.53709, size = 132, normalized size = 0.88 \begin{align*} \frac{5}{12} \,{\left (-10 \, x^{2} - x + 3\right )}^{\frac{3}{2}} x - \frac{7}{432} \,{\left (-10 \, x^{2} - x + 3\right )}^{\frac{3}{2}} + \frac{2675}{1728} \, \sqrt{-10 \, x^{2} - x + 3} x + \frac{648919}{1244160} \, \sqrt{10} \arcsin \left (\frac{20}{11} \, x + \frac{1}{11}\right ) - \frac{7}{243} \, \sqrt{7} \arcsin \left (\frac{37 \, x}{11 \,{\left | 3 \, x + 2 \right |}} + \frac{20}{11 \,{\left | 3 \, x + 2 \right |}}\right ) + \frac{3397}{20736} \, \sqrt{-10 \, x^{2} - x + 3} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x),x, algorithm="maxima")

[Out]

5/12*(-10*x^2 - x + 3)^(3/2)*x - 7/432*(-10*x^2 - x + 3)^(3/2) + 2675/1728*sqrt(-10*x^2 - x + 3)*x + 648919/12
44160*sqrt(10)*arcsin(20/11*x + 1/11) - 7/243*sqrt(7)*arcsin(37/11*x/abs(3*x + 2) + 20/11/abs(3*x + 2)) + 3397
/20736*sqrt(-10*x^2 - x + 3)

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Fricas [A]  time = 1.61113, size = 377, normalized size = 2.51 \begin{align*} -\frac{1}{20736} \,{\left (86400 \, x^{3} + 5280 \, x^{2} - 58356 \, x - 2389\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1} + \frac{7}{243} \, \sqrt{7} \arctan \left (\frac{\sqrt{7}{\left (37 \, x + 20\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{14 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) - \frac{648919}{1244160} \, \sqrt{10} \arctan \left (\frac{\sqrt{10}{\left (20 \, x + 1\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{20 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x),x, algorithm="fricas")

[Out]

-1/20736*(86400*x^3 + 5280*x^2 - 58356*x - 2389)*sqrt(5*x + 3)*sqrt(-2*x + 1) + 7/243*sqrt(7)*arctan(1/14*sqrt
(7)*(37*x + 20)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3)) - 648919/1244160*sqrt(10)*arctan(1/20*sqrt(10)*
(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3))

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(3/2)*(3+5*x)**(5/2)/(2+3*x),x)

[Out]

Timed out

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Giac [A]  time = 2.18038, size = 269, normalized size = 1.79 \begin{align*} -\frac{7}{2430} \, \sqrt{70} \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{70} \sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} - \frac{1}{518400} \,{\left (12 \,{\left (8 \,{\left (36 \, \sqrt{5}{\left (5 \, x + 3\right )} - 313 \, \sqrt{5}\right )}{\left (5 \, x + 3\right )} + 2385 \, \sqrt{5}\right )}{\left (5 \, x + 3\right )} + 79315 \, \sqrt{5}\right )} \sqrt{5 \, x + 3} \sqrt{-10 \, x + 5} + \frac{648919}{1244160} \, \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{4 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x),x, algorithm="giac")

[Out]

-7/2430*sqrt(70)*sqrt(10)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))^2
/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) - 1/518400*(12*(8*(36*sqrt(5)*(5*x + 3) - 313*sqrt(5))*
(5*x + 3) + 2385*sqrt(5))*(5*x + 3) + 79315*sqrt(5))*sqrt(5*x + 3)*sqrt(-10*x + 5) + 648919/1244160*sqrt(10)*(
pi + 2*arctan(-1/4*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x +
5) - sqrt(22))))